Markov process 的機率特性 (意指 pdf, fdd 等) 由 transition probability 完全決定。所以先介紹 transition probability 的前身 -- measure kernal :
Def. Measure Kernal
Let (X,A) and (Y,B) be measurable spaces. A measure kernal k is a function form X,B to R
that is a measure on B given a point in X, and an A-measurable given a event in B.
When the measure is a probability, k is called a probability kernal.
當 (Y,B) = (X,A) 的時候, probability kenals 可以`相乘’:
Def. Product of Probability Kernals
\mu and \nu are probability kernals, their product is defined as
where x is a point in X and B is a event in \mathcal{B}, sorry for the bad notations.
Remark. 我們可以把 k(x,B) 想像成一個 partical 從 x 出發,最後落到 B 的機率。上面的乘法 (\mu \nu)(x,B) 可以解釋成一個 partical 從 x 出發,先經過 y ,再落到 B 上的機率。
Remark2. 注意一下乘法的順序, \mu\nu 就好像是 \mu 作用在 \nu 上面。的確,按照定義 \mu 是當作 measure。
Example. When \mu is the delta distribution concentrated on x
then it is an identity
當然, Probability kernals 還可以跟 X 上的 measure 相乘:
可以解釋為 \pi 作用在 \mu 上面 (因為 \pi 作為 measure)。另外一個對偶的解釋是 \mu 作用在 \pi 上變成 X 上一個新的 measure 。
Def. Transition Semi-group
A transition semi-group is a collection of probability kernals
indexed by two time variable s and t (s<=t) such that
1) for all s equals to t
2) for all s<=t<=u
A transition semi-group is called time-homogeneous if
for all s and t.
Remark. Semi-group 就是有乘法、有結合律的集合。
Remark2. 實際上這是一個 Monoid ,因為 delta 扮演 identity 的角色。
我們知道給定 Markov process 有對應的 transition semi-group ,那給定 transition semi-group 是否有對應的 Markov process 呢?答案是肯定的。以下定理如是說:
Thm. Existence of Markov Process Give a Transition Semi-group
Given a transition semi-group and a collection of distribution \pi_t on (X,A) such that
for all s and t, then there exists a Markov process X(t) having the same probability kernals and distributions. The converse is also true that a Markov process defines a transition semi-group via
Remark. 證明存在就用 Kolmogorov ExtensionTheorem 。因為給定 transition semi-group 和一個初始 distribution 就足以決定所有的 fdd (finite dimensional distribution) ,且由於 transition semi-group 的定義,這些 fdd 一定 consistent 。
Thm. Markov property is preserved under coraser filter
If a Markov process is adapted to {g_t}, then it is still Markovian for all coraser filters.
沒有留言:
張貼留言